DC-DC Mini 5V Step-Up Power Boost Converter Module

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The dc-dc mini 5V step-up power boost converter module provides 5V DC stable voltage output at various input range - 0.9V, 1.5V, 1.8V, 2.5V, 3V, 3.3V, 3.7V, 4.2V to 5V (0.9-5V 600mA Mini).

The starting voltage of this converter module is 0.9V, the output current 7mA, and operates at a frequency 180KHz, the typical conversion efficiency is 85%. Using it can be made power bank, drivers for LED flashlights, etc.

It can boost the input voltage level and provides the amplified stabilized 5V output. For the different input ranges, the module consumes a different amount of current to produce a balanced output.

Mini 5V Step-Up Power Boost Converter Module Buy Now


Specification

  • Input Voltage: 0.9 to 5V
  • Output voltage: 5V
  • Maximum Output Current: 600mA
  • Starting Up Voltage: 0.9V; output current: 7mA
  • Input Voltage: 1-1.5V; output voltage 5V; current 40-100mA
  • Input Voltage: 1.5-2V; output voltage 5V; current 100-150mA
  • Input Voltage: 2-3V; output voltage 5V; current 150-380mA
  • Input Voltage: >3V; output voltage 5V; current 380-600mA
  • Typical Conversion Efficiency: 85%

Features

  1. Small in size - 1.1 x 1.05 x 0.75 cm module dimensions.
  2. Light-weight (2 Grams).
  3. Different power consumption for different voltages.

Pinout

The pinout (Vi, GND, Vo) is indicated on the mini 5V step-up power boost converter module:
  • Vi: Positive voltage input (paired with GND/min)
  • GND: Ground
  • Vo: Positive voltage output (paired with GND/min)

Mini 5V Step-Up Power boost converter module Circuit diagram

Schematic of the dc-dc mini 5V step-up power boost converter module circuit shown below.


Components used

The following components are used in this module.
  • U1 - ME2108 chip
  • L1 - 22uH choke
  • D1 - SS14 Schottky diode
  • C1, C2 - 12uF ceramic capacitors

Working principle of ME2108 5V Step-Up Step-Up converter circuit

The main component of this converter module circuit is a very popular ME2108 chip. The block diagram shows that everything necessary for operation is contained in the chip itself except for the rectifier Schottky diode, capacitors, and the boosting element the choke.


The most basic advantage of this microcircuit is an ultra-low idle current, but the maximum output current is 0.6 ampere, and is possible to increase it by a connection of an external transistor.

The circuit operates in a simple way the microchip (U1) itself can be accepted as a switch that works with a very high frequency more precisely 180 KHZ as the manufacturer indicates.

When the switch closes, the power from the battery goes to the choke (L1), and energy is accumulated in it. When the switch is opened due to self-induction, there is a surge voltage, which is several times higher than the supply voltage. The more energy pumped into the choke the more it keeps. The current and voltage depend on the parameters of the winding of the choke. This splash is then rectified into a direct current and accumulated in the parallel capacitors (C1, C2).

The chip feedback maintains voltage at 5 volts, when we connect the load to the output of the converter, it will actually be powered by the energy stored in the capacitors.

The switching accumulation and return of energy occur exactly 180 thousand times per second. Despite the pulse mode of operation of the microcircuit as well, the components of the circuit will heat up, or to be precise exactly 15% of initial power will be dissipated in the form of unnecessary heat.

Mini 5V Step-Up Power boost converter module Connection diagram

Connection diagram of Mini 5V Step-Up Power boost converter module
Connection diagram of the Mini 5v step-up power boost converter module.

While using this converter module one must comply with the following conditions:
  1. Input voltage cannot be greater than the nominal voltage. Otherwise, it will burn out the chip of the module.
  2. Input power must be greater than the output power. Otherwise, the output voltage will be less than the nominal voltage.
  3. Output load should be no more than the rated load. Otherwise, the output voltage will be less than the nominal voltage.

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